• Learning center

210. Circuit analysis of Wistron 15221 (HM170)- EC standby power gener
210. Circuit analysis of Wistron 15221 (HM170)- EC standby power generation process
Detail
Comments

1

00:00:00,466 --> 00:00:06,700

Hello everyone, today we continue to study the circuit timing of the Wistron 15221 motherboard,

2

00:00:10,233 --> 00:00:14,833

mainly learning how the EC standby condition is generated

3

00:00:20,300 --> 00:00:24,233

EC position number is U2407

4

00:00:24,766 --> 00:00:31,033

Directly search for "U2407" in the circuit diagram to find the EC

5

00:00:35,266 --> 00:00:48,600

Its model is IT8226E, which is consistent with the actual model

6

00:00:51,066 --> 00:00:59,033

The standby power supply of EC is usually AVCC or VSTBY

7

00:01:00,166 --> 00:01:03,366

These are the standby supply pins of the EC

8

00:01:04,600 --> 00:01:09,933

In addition to the pins AVCC and VSTBY.

9

00:01:10,966 --> 00:01:14,600

There are some other power supply pins next to it

10

00:01:14,933 --> 00:01:21,566

For example, VSTBY0 is also provided by 3D3V_ AUX_S5_EC

11

00:01:23,166 --> 00:01:25,466

Track down this power source

12

00:01:25,933 --> 00:01:29,533

Found it from 3D3V_AUX_S5

13

00:01:31,166 --> 00:01:38,566

Through the block diagram, it is found that it is output by RT6575D

14

00:01:41,033 --> 00:01:44,800

After searching, we found RT6575D

15

00:01:44,900 --> 00:01:47,733

Its position number is PU45011

16

00:01:48,000 --> 00:01:57,466

The LDO3 pin of this chip is a linear output pin, and the external name is 3D3V_ AUX_S5, which is its source

17

00:01:59,733 --> 00:02:03,700

Therefore, we can find through the timing diagram

18

00:02:04,300 --> 00:02:09,666

The external name of VSTBY0 pin of EC is 3D3V_ AUX_S5

19

00:02:10,933 --> 00:02:15,766

Provided by LDO3 of this PU4501 (standby chip)

20

00:02:17,566 --> 00:02:22,933

PU4501 is in the actual product, its actual model is "5X="

21

00:02:25,666 --> 00:02:28,700

This is a chip produced by Richtek

22

00:02:29,633 --> 00:02:32,700

Because the chip is relatively small

23

00:02:33,066 --> 00:02:37,600

It cannot print all the chip models on the chip surface

24

00:02:38,666 --> 00:02:42,733

Therefore, it uses this code to indicate the model of the chip

25

00:02:43,533 --> 00:02:50,433

When we encounter this kind of code in the maintenance process, but don't know its actual model

26

00:02:51,066 --> 00:02:57,233

In this case, you can find the actual model corresponding to it by querying the code name in this search bar

27

00:02:57,833 --> 00:03:06,133

Select "Signal original pass and search", input "5X="

28

00:03:06,366 --> 00:03:11,633

You can find that the actual model of "5X=" is RT6575D

29

00:03:13,000 --> 00:03:18,833

In the future, we will encounter codes on the surface of this chip in the maintenance process

30

00:03:20,066 --> 00:03:25,600

You can find the actual model of the chip by searching its code name in Xinzhizao

31

00:03:26,133 --> 00:03:31,333

Ok, let's take a look at the workflow of RT6575D

32

00:03:31,866 --> 00:03:35,866

Through the chip data sheet can be found

33

00:03:36,933 --> 00:03:44,766

For RT6575D to output LDO, it only needs to satisfy VIN

34

00:03:45,033 --> 00:03:51,300

After the main power supply of VIN, the LDO3 output will be generated

35

00:03:51,733 --> 00:03:59,933

When the output of LDO3 exceeds 2.5V, LDO5 will also start to output

36

00:04:00,100 --> 00:04:02,700

Ok, this is the LDO3 output condition

37

00:04:04,466 --> 00:04:08,366

We find "VIN" in the circuit diagram

38

00:04:09,366 --> 00:04:14,766

Its power supply comes from 19V_DCBATOUT, which is the common point voltage

39

00:04:15,400 --> 00:04:24,933

When the chip meets the VIN power supply, it will automatically output LDO3 (3D3V_ AUX_S5)

40

00:04:26,566 --> 00:04:35,000

Therefore, we can find from this timing diagram that when the common point of the small current is normal,

41

00:04:35,433 --> 00:04:39,266

it can provide the main power supply to the standby chip

42

00:04:39,766 --> 00:04:46,500

Then the standby chip will output the external name of LDO3

43

00:04:46,500 --> 00:04:51,200

as 3D3V_AUX_S5 to provide power to the VSTBY pin of the EC

44

00:04:52,400 --> 00:04:56,200

Then, after the VSTBY pin of the EC is powered, it will output a high-frequency XLP_OUT to

45

00:04:56,533 --> 00:05:05,033

control the generation of AVCC power supply

46

00:05:05,900 --> 00:05:08,333

Let's take a look at the source of AVCC

47

00:05:08,633 --> 00:05:11,933

The external name of the AVCC pin is also AVCC

48

00:05:12,866 --> 00:05:25,600

It comes from this 33 ohm resistor, which is renamed AVCC by 3D3V_AUX_KBC through the resistor,

49

00:05:25,666 --> 00:05:29,433

and then goes to provide standby power to EC

50

00:05:30,466 --> 00:05:42,666

3D3V_AUX_KBC also provides standby power to the VSTBY pin of the EC

51

00:05:43,766 --> 00:05:48,766

Let's take a look at the power generation source of 3D3V_AUX_KBC

52

00:05:49,900 --> 00:06:02,866

This power supply can be generated in two ways

53

00:06:02,866 --> 00:06:16,333

The first is to connect directly through a resistor, and rename 3D3V_AUX_S5 to 3D3V_AUX_KBC

54

00:06:17,300 --> 00:06:22,400

The second is to conduct through the MOS tube

55

00:06:24,133 --> 00:06:28,133

These two generation methods, the circuit will only use one of them

56

00:06:29,300 --> 00:06:33,200

We find Q2412, R2496, and R2493 by searching the component position number

57

00:06:34,466 --> 00:06:45,566

to see which method is used in the actual circuit

58

00:06:46,366 --> 00:06:49,200

It can be found from the actual object that the two resistors are not installed,

59

00:06:51,266 --> 00:06:58,600

that is to say, the two resistors 2496 and 2493 are empty.

60

00:06:58,600 --> 00:07:02,866

The resistor is not installed, indicating that the second method is used

61

00:07:04,033 --> 00:07:11,900

After being turned on by Q2412, the AVCC power supply and VSTBY of EC are generated

62

00:07:16,800 --> 00:07:19,566

This is a P-channel mode tube

63

00:07:21,033 --> 00:07:30,466

To make this 3D3V_AUX_S5 conduction, the G pole voltage must be less than the S pole voltage

64

00:07:31,166 --> 00:07:37,166

The G pole is connected to the 6th pin of Q2410

65

00:07:38,000 --> 00:07:49,200

If pin 6 is connected to ground, it can pull the G pole of Q2412 to low level

66

00:07:52,033 --> 00:08:05,266

The conduction condition of Q2410 is: the XLP_OUT signal must be greater than 2.5V (must be a high level)

67

00:08:06,100 --> 00:08:08,733

This high level comes from the EC

68

00:08:10,700 --> 00:08:19,633

After the EC receives power from VSTBY0, it sends a high-level control signal

69

00:08:20,800 --> 00:08:26,866

Control pins 1 and 6 of Q2410 to turn on, pull down the G pole of Q2412,

70

00:08:27,366 --> 00:08:32,700

make 3D3V_AUX_S5 flow to 3D3V_AUX_KBC,

71

00:08:32,866 --> 00:08:37,400

and provide standby power supply for VSTBY and AVCC pins of EC

72

00:08:41,233 --> 00:08:44,700

Ok, this is the EC's standby power generation process

No comments yet
Come and write your comments
Links: