• Learning center

45. Diode characteristics
45. Diode characteristics
Detail
Comments

1

00:00:02,100 --> 00:00:06,000

Hello everyone, in this lesson we will learn the characteristics of diodes

2

00:00:06,600 --> 00:00:09,000

There are actually many characteristics of diodes

3

00:00:09,300 --> 00:00:16,100

Moreover, when the diode works in different states, its characteristics are also different.

4

00:00:17,100 --> 00:00:21,800

Here we only talk about the characteristics of the diode when it works in the forward direction

5

00:00:22,500 --> 00:00:25,366

When the diode works in the forward direction,

6

00:00:25,666 --> 00:00:29,133

the most important characteristic is the one-way conductivity

7

00:00:29,933 --> 00:00:37,400

This means that the diode only allows current to flow from the positive pole to the negative pole,

8

00:00:38,266 --> 00:00:43,000

and does not allow current to flow from the negative pole to the positive pole

9

00:00:44,100 --> 00:00:48,333

There is another characteristic of the diode when it works in the forward direction,

10

00:00:48,333 --> 00:00:51,100

that is, there is a forward voltage drop

11

00:00:51,933 --> 00:00:54,933

Forward voltage drop is also called threshold voltage

12

00:00:55,700 --> 00:00:58,900

The threshold voltage of the silicon tube is 0.7 volts,

13

00:00:59,333 --> 00:01:03,100

and the threshold voltage of the germanium tube is 0.3 volts

14

00:01:05,166 --> 00:01:08,700

When understanding the forward voltage drop of a diode,

15

00:01:09,000 --> 00:01:13,400

a diode can be compared to a highway toll booth

16

00:01:14,000 --> 00:01:19,566

When passing through this toll booth, we need to pay 100 yuan

17

00:01:20,500 --> 00:01:29,000

If we brought 500 yuan, we only have 400 yuan left after passing through this toll booth

18

00:01:29,800 --> 00:01:36,266

If we have 50 yuan with us, we cannot pass through this toll booth

19

00:01:37,200 --> 00:01:41,566

Speaking of diodes, if this is a silicon tube

20

00:01:42,266 --> 00:01:46,433

The voltage drop across the silicon tube is 0.7 volts

21

00:01:46,866 --> 00:01:53,600

Input a voltage of 3 volts, and only 2.3 volts are left after passing through the diode

22

00:01:54,700 --> 00:02:00,866

According to these two characteristics of the diode, we can get the conduction condition of the diode

23

00:02:01,066 --> 00:02:04,100

That is, the positive pole is greater than the negative pole,

24

00:02:04,366 --> 00:02:10,233

and the voltage difference between the positive and negative poles is greater than the forward voltage drop

25

00:02:10,600 --> 00:02:14,800

The third characteristic is used after the diode is turned on

26

00:02:15,000 --> 00:02:22,033

That is, after the diode is turned on, the positive pole is greater than the negative pole

27

00:02:22,633 --> 00:02:29,533

We need to combine the following two circuit diagrams to understand the voltage drop of the diode

28

00:02:29,933 --> 00:02:37,500

We must first know that the voltage at the ground point and the power supply point will never change

29

00:02:37,966 --> 00:02:40,966

The point of grounding is always 0 volts,

30

00:02:41,366 --> 00:02:47,066

and the point connected to the power supply is always the voltage of the power supply

31

00:02:47,700 --> 00:02:54,033

Assuming both diodes are silicon diodes, they both have a voltage drop of 0.7 volts

32

00:02:55,366 --> 00:03:00,766

When the circuit diagram on the left is not working, the positive pole of the diode is 5 volts,

33

00:03:00,966 --> 00:03:03,766

and the negative pole is 0 volts.

34

00:03:04,200 --> 00:03:06,133

The positive pole is greater than the negative pole,

35

00:03:06,300 --> 00:03:08,933

and the voltage difference between the positive and negative poles

36

00:03:09,400 --> 00:03:11,600

is greater than the forward voltage drop of the diode

37

00:03:12,133 --> 00:03:14,033

Then the diode can conduct

38

00:03:16,500 --> 00:03:20,600

After conduction, the positive pole will only be 0.7 volts greater than the negative pole

39

00:03:21,133 --> 00:03:25,066

Observe the circuit diagram and connect the power supply to the anode of the diode

40

00:03:25,333 --> 00:03:29,033

Then the positive pole is always the power supply voltage, 5 volts

41

00:03:30,533 --> 00:03:33,666

In order to meet the third characteristic of the diode,

42

00:03:33,933 --> 00:03:37,700

the cathode voltage of the diode will become 4.3 volts

43

00:03:38,533 --> 00:03:41,533

Let's look at the circuit diagram on the right

44

00:03:42,000 --> 00:03:48,233

When the circuit is not working, the positive pole is 5 volts and the negative pole is 0 volts.

45

00:03:49,766 --> 00:03:51,666

The positive pole is greater than the negative pole,

46

00:03:52,166 --> 00:03:56,766

and the positive and negative voltage difference is greater than the voltage drop of the diode

47

00:03:57,266 --> 00:04:00,166

Then the diode can conduct

48

00:04:01,400 --> 00:04:04,366

We continue to observe this circuit

49

00:04:05,000 --> 00:04:09,300

It can be seen that the negative pole of the diode is directly grounded,

50

00:04:09,566 --> 00:04:13,033

so the negative pole voltage is always 0 volts

51

00:04:14,133 --> 00:04:21,033

In order to meet the third characteristic of the diode, only the anode voltage of the diode can change

52

00:04:22,633 --> 00:04:26,166

Positive voltage becomes 0.7 volts

No comments yet
Come and write your comments
Links: