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In this lesson we will take this motherboard as an example to learn the working process of the standby circuit
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First find the blueprint of this motherboard
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This mainboard is Gigabyte
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Its board number is GA-H110M-S2 and its version number is 1.0
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By searching we found the drawing
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Open the drawing, at the same time we also found the bitmap, open the bitmap
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Next, let's take a look at the standby part of the hard boot of the 100 series mainboard.
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The first step is to supply power to the mainboard by a 3V button battery when the power supply is not plugged in.
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After circuit conversion, the 3V button battery will generate a power supply for the RTC of the bridge
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Let's find this part of the circuit in the mainboard
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We first find the button battery in the physical picture
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Button batteries can be seen here
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Then find the position number of the button battery in the bitmap
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Its position number is BAT
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Search for the position number in the circuit diagram to find the coin cell battery in the circuit diagram
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Let's take a look at this part of the circuit
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First of all, we need to know that the button battery is generally 3.3V
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The electricity of the button battery will generate a N_RTCVDD power supply through the common cathode diode
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Let's search for this power supply and see where it goes
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It can be seen that this power supply is supplied to the VCCRTC pin of PCH
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Then this power supply is used to supply power to the RTC circuit of the bridge.
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At this time, the first step of the sequence has been generated
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Let's draw this step briefly
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Let's look at the second step of the timing
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The second step of the timing sequence is to give the bridge a high-level RTCRST# signal
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after the electricity of the button battery is converted by the circuit.
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Just when VCCRTC was generated, VCCRTC has been pulled up
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N_RTCRST signal
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Let's search for this signal to see where it goes
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As you can see, it is first connected to the RTCRST# pin of the bridge
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This pin is the reset of the RTC circuit
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There is another signal below this signal called SRTCRST#
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Here is also pulled high by VCCRTC
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At the same time, this RTCRST is also connected to a jumper cap
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This jump cap we generally call it a CMOS jump cap
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Then the second step of the timing has also been completed.
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Let's briefly draw this step
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Let's look at the third step of the timing
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In the third step, after the bridge receives the power supply and reset signal of the RTC circuit,
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it will supply power to the crystal oscillator and let the crystal oscillator start to oscillate.
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This crystal oscillator is a 32.768KHz crystal oscillator, which is the crystal oscillator of the RTC circuit
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The crystal oscillator pin of the general bridge is RTCX
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We search for RTCX directly in the circuit diagram
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It can be seen that it is connected to a 32.768KHz crystal oscillator
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In this step we also draw it
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After the crystal oscillator of the RTC circuit also starts to oscillate, the RTC circuit is over.
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Next, let's look at the timing and see what the next step is
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Observing the hard start sequence, we can know that it is the turn of the power supply next
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As long as the ATX power supply is connected to the power supply, it will generate purple 5V, also called 5VSB
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This power supply is uncontrolled
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As long as the power supply has power, it will generate
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Let's find this purple 5V in the circuit diagram
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First find the ATX socket on the mainboard
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It can be seen here that the 5VSB of the purple 5V is the fourth pin from the top to the bottom on the left
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In the real thing, this pin is purple 5V
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Let's draw this purple 5V first
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After the purple 5V is available, it will be converted into a 3.3V voltage by a voltage regulator
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This 3.3V voltage is the deep sleep standby voltage, which is mainly used to power the bridge and IO
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We generally call this power supply VCCDSW_3P3
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This is also a standby condition for the bridge
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Let's find this VCCDSW_3P3 in the circuit diagram
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As you can see, its external name is 3VDUAL_PCH
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Let's search for this power supply to see how it is generated
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After searching, it is found that it is generated by purple 5V through a voltage regulator
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Let's find this voltage regulator in the physical picture
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The model number of this regulator is 1117
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The appearance of the voltage regulator is similar to the symbol in this circuit diagram
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Let's look in the real thing to see if there are similar components
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It can be seen that there is a similar component on the lower right foot of the bridge
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Its position number is NQ9
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Let's go back to the circuit diagram
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It can be seen that the position number of this regulator is also NQ9
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Then this regulator tube is the conversion regulator tube of VCCDSW_3P3
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Let's also briefly draw this step
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After this power supply is generated, it will first give to the VCCDSW_3P3 of the bridge
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Let's see where else this power supply goes
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Continue searching for 3VDUAL_PCH in the circuit diagram sequentially from top to bottom
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It can be seen that in this circuit,
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3VDUAL_PCH replaces the button battery and supplies power to the RTC circuit of the bridge.
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The purpose of this is to save the power of the button battery
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When plugged in, it uses the power of the power supply instead of the button battery
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Prevent the button battery from being consumed too quickly,
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so you don't need to replace the battery frequently
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Let's go down and see where else it's gone
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It can be seen here that it is renamed IT_VCCH through a direct-connected L zero-ohm resistor
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This IT_VCCH is the IO power supply
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This IO is on the lower left foot of the mainboard
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You can see that it is given to the 3VSB pin of the IO
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Let's draw this step as well
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Let's move on to the timing next step
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After the IO detects that the voltage is normal, it will send a deep sleep standby voltage good signal to the bridge
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This deep sleep standby voltage good signal is DSW_PWROK
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Let's search for this DSW_PWROK
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Search for DSW_PWROK in the circuit diagram
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As you can see, its external name is N_PCH_DPWROK
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Let's search for this signal to see where it's coming from
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It is pulled up by 3VDUAL_PCH here
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While 3VDUAL_PCH has generated
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So the pull-up voltage already exists
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Next he also connects to the IO
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When IO has 3VSB power supply, it will issue this N_PCH_DPWROK
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So at this time, the signal has already been generated
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Let's draw this step as well
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Next, after the bridge receives VCCDSW_3P3 and DSW_PWROK, it will send SLP_SUS# signal
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This signal is mainly used to control the main standby voltage, which is VCCPRIM_3P3
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Next, let's take a look at how VCCPRIM_3P3 is generated in the circuit diagram
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Search for VCCPRIM_3P3 in the circuit diagram
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Its external name is VCC3_PCH
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Search for VCC3_PCH
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It can be seen that it is directly converted from 3VDUAL
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We search 3VDUAL
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There are many places where 3VDUAL is connected.
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Let's take a look at it in turn to see where it comes from.
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It can be seen that 3VDUAL is also generated by a voltage regulator
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It's just that the model of this regulator is L1085D
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And its input voltage is not 5VSB, but 5VDUAL
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Let's first find this voltage regulator in the physical picture
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You can see this regulator here, its position number is Q4
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Although this voltage regulator can directly generate 3VDUAL,
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the power supply of the voltage regulator is the input 5VDUAL,
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and we haven't found its source yet.
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We then look for the source of this 5VDUAL
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We found the source of 5VDUAL here
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It can be seen that it connects two MOS tubes
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The MOS tube above is an N-channel MOS tube
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The MOS tube below is a P-channel MOS tube
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This is Gigabyte's characteristic circuit, dual 5V power supply
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5VDUAL is connected to VCC through an N-channel MOS transistor, which is the red 5V after triggering
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Here is a P-channel MOS tube
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5VDUAL is connected to 5VSB through a P-channel MOS tube, which is the purple 5V before power-on
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When the lower tube is turned on, 5VDUAL and 5VSB are connected
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When the upper tube is turned on, 5VDUAL is connected to VCC
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It has not been triggered yet, so the MOS tube below should be turned on
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It is a P-channel MOS tube
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P-channel MOS transistor low-level conduction
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Let's find P_EN and see how it becomes low
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As you can see, it is connected to 5VAUX_SW
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We search for 5VAUX_SW and we can see that it is connected to IO
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This 5VAUX_SW is pulled low after the IO has power supply,
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and does not use the SLP_SUS signal sent by the bridge.
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So there is a low-level 5VAUX_SW signal here, and then there is a 5VDUAL power supply
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With 5VDUAL power supply, there is 3VDUAL power supply
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Let's draw this step a little bit
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After the 3V power supply is generated, the 3V power supply will supply power to the VCCPRIM_3P3 of the bridge
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Then this 3V standby voltage will generate 1V standby voltage, also called VCCPRIM_1P0
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Search for VCCPRIM_1P0 in the circuit diagram
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As you can see, its external name is VCC1_0_PCH
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Let's search for this power supply to see how it is generated
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This power supply is generated by the PWM circuit
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The chip for this PWM is here
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The working process of this chip is very simple, as long as there is power supply and open signal, it will have output
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Its power supply comes from 5VDUAL, which has generated
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And its turn-on signal has not been found
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Let's search
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It can be seen that its turn-on signal comes from this circuit
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These MOS tubes are not installed, all are crossed
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And this is directly connected
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That is to say, the 1V EN signal is directly pulled up by the 3VDUAL through the 8.2k resistor.
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With the power supply, after it is turned on, it will generate a 1V standby voltage
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Let's draw this step as well.
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The power supply comes from 5VDUAL, turn on the pull-up from 3VDUAL
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With the power supply and open signal, the power supply of VCCPRIM_1P0 will be generated
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Next we come to the last step of looking at the machine
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After the IO detects that the standby voltage is normal, it will send a good standby voltage signal RSMRST#
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Let's search for RSMRST#
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You can see that there is an RSMRST here, and an RSMRST here
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The above RSMRST is pulled up by 3VDUAL through a 22K resistor
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And the following RSMRST
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None of these components are installed, let's see where RSMRST went
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It can be seen that it is connected to the bridge and connected to the 114 pin of the IO
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Let's find out if he is still connected to other places
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There is none left
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This signal is pulled up to the bridge by 3VDUAL after it is sent by IO
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But the hard start here says that the IO will send out the RSMRST# signal
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after it detects that the standby voltage is good.
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IO is through pin 95 to judge whether the main standby is normal
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We search for its external signal name and we can see that it is converted from 3VDUAL through a 100 ohm resistor
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3VDUAL is now normal, then the 95 pin of IO will have 3V power supply
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IO will send a high-level RSMRST# signal
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Let's draw this step as well
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After IO gets SUS_3VSB, it will send RSMRST# signal
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The main function of RSMRST# is to give the bridge to tell the bridge that the standby voltage is normal
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Well, so far the standby circuit is over